If f(x)=2x1 and g(x)=3x2 then find (fog) (x) A 2(3x1) B 2(3x2) C 3(2x1) D 3(3x1) Medium Open in App Solution Verified by Toppr Correct option is C 3(2x1)It must be in terms of f (x)∵ ƒ(x) = ( x 1 ) / ( x 1 ) (1) ∴ ( x 1 ) ƒ(x) = x 1 ∴ x ƒ(x) ƒ(x) = x Thank you for registering One of our academic counsellors will contact you within 1 working dayCorrect Answer Option (d) Solution f (g(x)) = 2 − 1 − 2x For given function to be defined, 1 − 2x ≥ 0 ⇒ x ≤ 21 And 2 − 1 − 2x ≥ 0 ⇒ 1 − 2x
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F(x)=x-1/x 1 then f(2x)-For example, if f is a function that has the real numbers as domain and codomain, then a function mapping the value x to the value g(x) = 1 / f(x) is a function g from the reals to the reals, whose domain is the set of the reals x, such that f(x) ≠ 0 The range of a function is the set of the images of all elements in the domainSimple and best practice solution for f(x)=2x1 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand,
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f (x) = 2x^2x3 g (x) = x 1 (f*g) (x) = f (x)*g (x) = (2x^2 x 3)* (x 1) = 2x^3 x^2 3x 2x^2 x 3 = 2x^3 x^2 4x 3 All real numbers can be plugged into this function, so its domain is that of all real numbers 👍Question If f(x) = 2x 1 and g(x) = (x – 1)/2 , then f(g(x)) = So, I know what to do Basic plug and chug I also know that the answer is X, I just don't know how to get to the answer I plug in g(xExperts are waiting 24/7 to provide stepbystep solutions in as fast as 30 minutes!* See Answer *Response times may vary by subject and question complexity Median response time is 34 minutes for paid subscribers and may be longer for promotional offers
Solution for f(x) = {x 2 if x > 1 (2x – 1 if x < 1 then f '( 2,4 ) is then f(2,4) is 1,2 and f is not continuous None of the choices 1,2 and f is ️⇒ x = y(1 x^2) ️⇒ yx^2 – x y = 0 N e e d a G F if anyone Girl single then com eygeweubexi id 247 154 9306 pas पूर्ण कोण किती मापाचा असतो?Evaluate f(x h) f(x)/h when f(x) = 3x 1 Find the vertex of f (x) = 2x^2 8x 9 Find f(g(x)) = f g when f(x) = x^2 2 and g(x) = x 3 Find f^1(x) when f(x) = 5x 2 Find f^1 (f(x)) when f(x) = 8 x Question Find f(3) when f(x) = 5x 1 If f(x) = 2x 5 and g(x) = x^2 4, then find f(x) middot g(x)
The value of f(x 1) = x² 4 Stepbystep explanation Given, f(x 1) = x² 4x 8 => f(x 1 1) = (x 1)² 4(x 1) 8 => f(x) = x² 2x 1 4x 4 8Explanation The function g(x) is equal to 4x 5, and the notation 2g(x) asks us to multiply the entire function by 2 2(4x 5) = 8x 10 We then subtract 3, If f (x) = x1/x1 then find the value of f (2x) Find the answer to this question along with unlimited Maths questions and prepare better for JEE examination
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Please answer this question if you know the answer then only answer else reported what will be the answer ☹️☹️☹Let's use the quadratic formula to solve for x Starting with the general quadratic the general solution using the quadratic equation is So lets solve ( notice , , and ) Plug in a=1, b=2, and c=1 Negate 2 to get 2 Square 2 to get 4 (note remember when you square 2, you must square the negative as well This is because )Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
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Questions from Relations and Functions 1 The domain of the function 2 If f(x) = 1 x2 4x 4 − 4 x4 4x3 4x2 4 x3 2x2 , then f(1 2) is equal to 3 The domain of the function 4 Iff( x 1 2x − 1) = 2x, X ∈ N, then the value of is equal to f(2) is equal to Answer to If f(x) = x2 3 and g(x) = (2x 1)1/2 then (f o This problem has been solved! Let \\(f(x) = \\begin{cases} ax^21 &, x>1 \\\\ x\\frac{1}{2} & , x \\leq 1 \\end{cases},\\) Then, f(x) is a = 2 B a = 1 C a = 0 D a = 1/2
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Simple and best practice solution for f(x)=2x1 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve it Ex 12, 10 Let A = R − {3} and B = R − {1} Consider the function f A → B defined by f (x) = ( (x − 2)/ (x − 3)) Is f oneone and onto?The statement "if f(x) = 1" tells me you are defining the function f to have the property that f(x) = 1 regardless of the value of x This is a particularly uninteresting function It is like a broken bathroom scale that always gives the same weight regardless of who stands on it Now look at f(f(x)) = 2x 4 What I see is f(f(x)) = 2x 4
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It can be written as, f (x) = ` { (1 x , 0 ≤ x ≤ 1) , (1 x, 1< x ≤ 2) , ( 3 x, 2 < x ≤ 3)}` When, 0 ≤ x ≤ 1 Then , `f (x) = 1 x ` Now when , 0 ≤ x ≤ 1 then ,1 ≤ x 1 ≤ 2 Then , `f (f (x))` = 1 (1 x ) = 2 x ∵ 1 ≤ f (x) < 2 When ,1 < x ≤ 2 Then , f (x) = 1 x Now when , 1 < x ≤ 2 then,2 < x 1 f(x) = {(3x)/(1x)} 23x taking log on both sides log(fx) = (2 3x) log {(3x)/(1x)} log(fx) = (2 3x) log(3x) log(1x) Now differentiate f'(x) /f(x) = (2Previous page to draw the graphs of f(x 2),f(x 2), f(2x), f(1 2x), and f(x) We could alternatively write these functions as (x 2)2,(x 2)2, (2x) 2,(x 2) ,and(x) The graphs of these functions are drawn on the next page Notice on the next page that the graph of (x)2 is the same as the graph of our original function x 2 That's because when
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If f x x 2 2 x 3 then f1 a 2 b 2 c 3 d 7 find f 4 6 If f (x)=x2−2x3, then f(1)=______ A – 2 B 2 C 3 D 0 7 Find f ( −4 ) when f (x)=x2−5x−1 A 37 B 35C – 5 D – 3 8 Given f(x)=x23 and g(x)=2x−1 f(x) = 2x Checking oneone f (x1) = 2x1 f (x2) = 2x2 Putting f(x1) = f(x2) 2x1 = 2 x2 x1 = x2 Hence, if f(x1) = f(x2) , x1 = x2 ∴ function f is oneone Onto f(x) = 2x Let f(x) = y, , such that y ∈ R 2x = y x = 𝑦2 Since y is a real number, Hence 𝑦2 will also be a real number So, x will also be a real number, ie, x ∈ RIf F(X) = X2 − 3x 4, Then Find the Values of X Satisfying the Equation F(X) = F(2x 1) 0 Department of PreUniversity Education, Karnataka PUC Karnataka Science Class 11
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The notation f −1 is sometimes also used for the inverse function of the function f, which is not in general equal to the multiplicative inverse For example, the multiplicative inverse 1/(sin x) = (sin x) −1 is the cosecant of x, and not the inverse sine of x denoted by sin −1 x or arcsin x Only for linear maps are they strongly related To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW If `f(x)=(x1)/(x1)` then `f(2x)` is equal toDivide f2, the coefficient of the x term, by 2 to get \frac{f}{2}1 Then add the square of \frac{f}{2}1 to both sides of the equation This step makes the left hand side of
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If f(x) = ∫(5x8 7x6)/(x2 1 2x7)2dx, (x ≥ 0) and f(0) = 0, then the value of f(1) is (1) 1/4 (2) 1/2 (3) 1/4 (4) 1/2The domain of the function 2 If f(x) = 1 x2 4x 4 − 4 x4 4x3 4x2 4 x3 2x2 , then f(1 2) is equal to 3 The domain of the function 4 Iff( x 1 2x − 1) = 2x, X ∈ N, then the value of is equal to f(2) is equal to 5 If n(A) = 5 and n(B) = 7, then the number of relations on A × B isThe trick here, such as it is, is simply realizing that we can use 2 as our ingredient if we figure out how to express it in the form 2x1 2x1 = 2 2x11 = 21 2x=3 2x/2 = 3/2 x=3/2 If we set x=3/2, then 2x1 = 2, so we can see that f (2) = f (2x1) = x when x = 3/2, or f (2) = f (2 (3/2)1) = 3/2
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If f (x) = x1/x1 then f (2x) is ?Divide \frac {f1} {f}, the coefficient of the x term, by 2 to get \frac {1} {2}\frac {1} {2f} Then add the square of \frac {1} {2}\frac {1} {2f} to both sides of the equation This step makes the left hand side of the equation a perfect square Square \frac {1} {2}\frac {1} {2f}8 Assume f ( x 1) = f ( x 2) Then x 1 2 1 = f ( f ( x 1)) = f ( f ( x 2)) = x 2 2 1 and so x 2 = ± x 1 Then from f ( f ( − x)) = f ( f ( x)) we conclude that f ( − x) = ± f ( x) for all x Define g 0, ∞) → 0, ∞) by g ( x) = f ( x) For x with g ( x) = f ( x) we have
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About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features Press Copyright Contact us CreatorsIf v (x) is larger of e x − 1 and (1 x) lo g (1 x) for x ϵ (0, ∞) then l o g (v (8) 1) is equal to View solution Let f ( x ) = 2 x tan − 1 x , g ( x ) = lo g ( 1 x 2 ) , h ( x ) = sin x u ( x ) = x − 6 x 3 1 2 0 x 4 then Determining Whether the Inverse Function Is a FunctionGraphically, f −1(x) = −x 1 2 −x would look like graph { (x1)/ (2x) 10, 10, 5, 5} In the graph above, you can see that the x and y values approach the vertical and horizontal asymptotes Since it resembles that of an exponential graph, there is only one y value for an x value
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Graph f (x)=x^22x1 f (x) = x2 2x − 1 f ( x) = x 2 2 x 1 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 2 x − 1 x 2 2 x 1 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b bF ( 2 x − 1) = f ( 2 ( 2 x − 1) 1) f ( 2 x − 1) = f ( 2 x 1 − 1) Note that the general solution is f ( x) = Θ ( log 2 ( x 1)) , where Θ ( x) is any periodic function with unit period So if the domain of f can be restricted to f ( − 1, ∞) → R , then f can be nonconstant and can be Θ ( log 2 F (g (2)), g (x)=2x1, f (x)=x^2 \square!
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Justify your answer f (x) = ( (x − 2)/ (x − 3)) Check oneone f (x1) = ( (x"1 " − 2)/ (x"1" − 3)) f (x2) = ( (x"2 " − 2)/ (x"2" − 3)) Putting f (x1) = f (x2) ( (x"1 " − 2)/ (x"1" − 3)) = ( (x"2 " − 2)/ (x"2" − 3)) Rough Oneone Steps 1See the answer See the answer See the answer done loadingOne way of solving is f(x) = log(1x/1x) f(x) = log(1x) log(1x) To find the given function replace x with (2x/1x^2) f(2x/1x^2) = log(1(2x/1x^2)) log(1(2x/1x^2)) f(2x/1x^2) = log((x^212x)/(1x^2))log((x^212x)/(1x^2)) On simpli
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F(x) = x2 1 x3 4x is a rational function, it is continuous everywhere in its domain, which is everywhere that the denominator is nonzero The denominator is zero at x= 0 and x= 2 6 If f(x) = (x2 3x)(6x5 2x8), compute f0(1) Solution f0(x) = (2x 3)(6x5 2x8) (x2 3x)(30x4 16x7) f0(1) = 5 4 4 14 = 76 7 For f(x) = 3 p x5 6 p 5 x3Algebra Graph f (x)= (2x1)/ (x1) f (x) = 2x − 1 x − 1 f ( x) = 2 x 1 x 1 Find where the expression 2x−1 x −1 2 x 1 x 1 is undefined x = 1 x = 1 Consider the rational function R(x) = axn bxm R ( x) = a x n b x m where n n is the degree of the numerator and m m is the degree of the denominator 1
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